LeetCode Python
LeetCode Python:
LeetCode is a platform for practicing coding skills and preparing for programming interviews. It features numerous problems on various topics such as arrays, strings, linked lists, trees, etc. These problems can be solved using different programming languages, including Python. I can guide you through a sample problem so you can understand how to approach LeetCode problems using Python.
Let’s take a popular problem as an example:
Problem: “Two Sum”
Description: Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return the answer in any order.
Example:
Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Because nums[0] + nums[1] == 9, we return [0, 1].
Python Solution:
def twoSum(nums, target):
# Create a dictionary to store the value and its index
lookup = {}
# Loop through the list of numbers
for i, num in enumerate(nums):
# Calculate the difference needed to reach the target
diff = target - num
# Check if this difference is in the lookup table
if diff in lookup:
# If it is, return the current index and the index of the difference
return [lookup[diff], i]
else:
# If not, add the number and its index to the lookup table
lookup[num] = i
# If no solution is found, return an empty list
return []
This function works by maintaining a lookup table (a dictionary in Python) where the keys are the numbers from the input list and the values are the corresponding indices. For each number, we calculate the difference that would add up to the target and then check if this difference is already present in the lookup table. If it is, we have found a solution. If not, we add the current number and its index to the lookup table and continue the process with the next number. The time complexity of this solution is O(n), where n is the length of the input list.
I hope this explanation is clear. Please feel free to ask if you have any questions or if you want me to cover another LeetCode problem.
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